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  • A certain transmittor radiates  9 W power while transmitting unmodulated carrier wave . If the amplitude of carrier wave voltage varies sinusoidilly , the peak voltage of carrier wave would be

A certain transmittor radiates  9 W power while transmitting unmodulated carrier wave . If the amplitude of carrier wave voltage varies sinusoidilly , the peak voltage of carrier wave would be (take antenna resistance = 50 \Omega)

Option: 1

15 V 


Option: 2

30 V 


Option: 3

30 /\sqrt 2 V


Option: 4

900 V 


Answers (1)

best_answer

As we have learned

Carrier Power -

P_{c}= \frac{\left ( \frac{E_{c}}{\sqrt{2}} \right )^{2}}{R}= \frac{E^{2}_{c}}{2R}
 

- wherein

E_{c}= Amplitude of carrier wave

R = Resistance

 

 We know that power of carrier wave is given by P_c = \frac{E_{c}^{2}}{2R}\; \; \; where E_c = peak \; \; \; amplitude \; \; of \: \: carrier \; \; wave

  Now P= 9 W

R = 50 \Omega

E_c = \sqrt{2 RP_c}\: \: volt

E_c = \sqrt{2 \times 9\times 50}\: \: volt

E_c = 30 volt

 

 

 

Posted by

Shailly goel

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