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A conductor of 3 m in length is moving perpendicularly to magnetic field of 10^-3 Tesla with the speed of 10² m/s , then the e.m.f. produced across the ends of conductor will be

Option: 1

0.03 volt

Option: 2

0.3 volt

Option: 3

3×10^-3 volt

Option: 4

3 volt

Answers (1)

best_answer

$e=B v l=3 \times 10^{-3} \times 10^{2}=0.3 \text { volt }$

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Riya

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