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  • a gas is allowed in a wel insulated container against aconstant external pressure of 2.5atm from an inital volume of 2.50L to final 4.50

He said to find out internal energy ^U ?

so i got ans is;

formula ; W=P*(V2-V1)

OPTIONS;A;-500j

                B;  -505j

                 C; +505j

                   D;1136.25j

MY ANS ; -500J

Answers (1)

It is given that the process is adiabatic

Hence, \Delta U +W =0

\Rightarrow \Delta U = -W

W = P\Delta V

W = 2.5\times 1.01\times 10^{5}\left ( 4.5 -2.5 \right )10^{-3}

W = 505\: J

\Delta U = -505 J

Posted by

Abhishek Sahu

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