A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L 

to a final volume of 4.50 L. The change in internal energy  \Delta U of the gas in joules will be :

Answers (1)

P =2.5\: atm

v_{i}=2.50L

v_{f}=4.50L

\Delta U=?

Word done,

W = -P \Delta v

=-2.5\left ( 4.50-2.50 \right )

=-5L-atm

=-5\times 101.3 J

=-506.5J

Now, for adiabate process, f=0

\therefore \Delta U=f+w

=-506.5J

=-505J

Most Viewed Questions

Preparation Products

Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Test Series JEE Main 2024

Chapter/Subject/Full Mock Tests for JEE Main, Personalized Performance Report, Weakness Sheet, Complete Answer Key,.

₹ 7999/- ₹ 4999/-
Buy Now
JEE Foundation + Knockout JEE Main 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports,.

₹ 3999/-
Buy Now
Knockout VITEEE 2023

An exhaustive program for the complete preparation of Physics Chemistry Mathematics English and Aptitude of VITEEE, Adaptive Time Table, Chapterwise Questions, Concepts Flashcards for Quick and Effective Revision, Unlimited Chapter wise Subject wise and Full mock test for enhancing Speed & Accuracy,.

₹ 2999/- ₹ 1999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions