A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L 

to a final volume of 4.50 L. The change in internal energy  \Delta U of the gas in joules will be :

Answers (1)

P =2.5\: atm

v_{i}=2.50L

v_{f}=4.50L

\Delta U=?

Word done,

W = -P \Delta v

=-2.5\left ( 4.50-2.50 \right )

=-5L-atm

=-5\times 101.3 J

=-506.5J

Now, for adiabate process, f=0

\therefore \Delta U=f+w

=-506.5J

=-505J

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