A gaseous hydrocarbon gives upon combustion 0.72 g . of water and 3.08 g. of Co2.The empirical formula of the hydrocarbon is :

Option 1)  C7H8

Option 2)  C2H4

Option 3)  C3H4

Option 4)  C6H5

Answers (1)

As we learnt,

Empirical formula -

An Empirical formula represents the simplest whole number ratio of various atoms present in a compound.

- wherein

for glucose, empirical formula is CH2O

 

General  equation for combustion of hydrocarbon :

C_{x}H_{y} + \left ( x + \frac{y}{4} \right ) O_{2} \rightarrow xCO_{2} + \frac{y}{2}H_{2}O

Number if moles of CO2 produced = 3.08 / 44 = 0.07

Number of moles of H2O produced = 0.72 / 18 = 0.04

  \text{So, } \frac{x}{\left ( \frac{y}{2} \right )} = \frac{0.07}{0.04} = \frac{7}{4}

The formula of hydrocarbon is C7H8.

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