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  • A man of mass (m_A) is sitting in a train movingwith velocity v_1 = 3 m/s . He observe that a block of mass m_B is moving towards him with v

A man of mass (m_A) is sitting in a train movingwith velocity v_1 = 3 m/s . He observe that a block of mass m_B is moving towards him with velocity v_2 = 5 m/s. Then the kinetic energy of block w.r.t  man is (Assume m _B= 5 Kg)

Answers (1)

 K.E of the block from the reference frame of the train is 

\frac{1}{2} m (v_1+ v_2) ^2

\\=\frac{1}{2} \times 5 \times [ 3+5] ^2 = 1/2 \times 5 \times 64\\ \\ =5 \times 32 = 160 J

Posted by

Safeer PP

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