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A plane monochromatic light falls normally on a diaphragm with two narrow slits separated by a distance \mathrm{d=2.5 \mathrm{~mm}.} A fringe pattern is formed on the screen placed at \mathrm{D=100 \mathrm{~cm}} behind the diaphragm. If one of the slits is covered by a glass plate of thickness \mathrm{10 \mu \mathrm{m},} then distance by which these fringes will be shifted will be

Option: 1

2 mm


Option: 2

3 mm


Option: 3

4 mm


Option: 4

5 mm


Answers (1)

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\mathrm{\begin{aligned} & \frac{x d}{D}(\mu-1) t \Rightarrow x=\frac{(\mu-1) t D}{d} \\\\ & \text { or } x=\frac{(1.5-1) \times 10^{-3} \times 100}{0.25}=0.2 \mathrm{~cm} \end{aligned}}

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