A ray of light is sent along the line 3x + y - 7 = 0. Upon reaching the line 3x - 2y + 5 = 0, the ray is reflected from it. Then the equation of the line containing the reflected ray is
3x + 41y + 161 = 0
3x - 39y + 161 = 0
3x - 41y + 161 = 0
3x + 39y + 161 = 0
Reflection of Light -
Reflection of Light
Laws of reflection
The incident ray, the normal ray and the reflected ray to a surface at the point of an incident all lie on the same plane.
The angle of incident = angle of reflection
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As from the figure,
To get coordinate of P, solve the equation of line together
3x + y - 7 = 0
3x - 2y + 5 = 0
We get, P = (1, 4)
Let, the slope of reflected ray is m
The slope of mirror line is 3/2
Then the slope of the line perpendicular to mirror line is (i.e. PN) -2/3
and slope of the incident ray is -3
Line PN is equally inclined to the line PR and IP
3x - 41y + 161 = 0
Altair
IMAGE METHOD
Choose A(0, 7) any point on reflected ray i.e. IP
And let B(α, β) is the image of point A about the mirror line 3x - 2y + 5 = 0, then
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