A ray of light passing through the point (2, 4) is reflected on the x-axis at a point P and passes through the point (5, 3). Then the abscissa of the point P is
-26/3
-26/7
26/3
26/7
Reflection of Light -
Reflection of Light
Laws of reflection
The incident ray, the normal ray and the reflected ray to a surface at the point of an incident all lie on the same plane.
The angle of incident = angle of reflection
-
Let N be the image of M (5, 3) with respect to x-axis. Thus N is (5, –3)
Slope of NQ =
Therefore, the equation QN is
7x + 3y = 26
Point P is (26/7, 0)
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