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A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of g0, the value of acceleration due to gravity at the earth's surface, is

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Gravitational potential energy at height 'h' -

U_{h}=-\frac{GMm}{R+h}

U_{h}=-\frac{gR^{2}m}{R+h}

U_{h}\rightarrow Potential energy at height h

R\rightarrow Radius of earth

- wherein

U_{h}=-\frac{mgR}{1+\frac{h}{R}}

 

 total energy of satelliteis equal to half of its potential energy.

\therefore E= \frac{-G m_{s}.Me}{2(R+h)}

\because g.=\frac{GMe}{R_{2}}  or  GMe = g_{0}R^{2}

E =\frac{ g_{0} m_{s}.R^{2}}{2(R+h)}

 

 

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lovekush

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