A think tube sealed at both ends is 100 cm long. It lies horizontally, the middle 20 cm containing mercury and two equal ends containing air at standard atmospheric pressure. if the tube is now turned to a vertical position, by what amount will the mercury be displaced?
(Given: cross section of the tube can be assumed to be uniform)
2.95 cm
5.18 cm
8.65 cm
0.0 cm
Let A and B are two chamber
When the tube is horizontally placed
Where a is an area of chambers
When the tube is vertically placed
let by d amount will the mercury be displaces
So new pressure in chambers are
and
From
Boyle's law:
For chamber A
For the chamber B
on Solving we get
d=5.18 cm
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