An element having FCC structure containing 12.08×10^23 atoms in unit cell,  The total number of atoms in the cell is

 

Answers (1)

Lattice points in BCC are at corners and body center of unit cell.

For body centered cubic (BCC), Z=2

We know, number of atoms = Z \times number\ of\ unit\ cells                             

\\ = 2 \times (12.08 \times 10^{23}) \\ = 24.16 \times 10^{23}

Thereore, total number of atoms are 24.16 \times 10^{23}

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