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  • Answer please! 6.02 x 1020molecules of urea are present in 100 mL of its solution. The concentration of the solution is:

6.02 x 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:

  • Option 1)

    0.01 M

  • Option 2)

    0.001M

  • Option 3)

    0.1M

  • Option 4)

    0.02M

 

Answers (1)

best_answer

As learnt in

Molarity -

 Molarity (M) = (Number of moles of solute)/(volume of solution in litres)

 

- wherein

It is defined as the number of moles of the solute in 1 litre of the solution.

 

No. of molecules (given) = 6.02 \times 10^{20}

No. of moles = \frac{6.02 \times 10^{20}}{6.02\times 10^{23}}= 10^{-3} \: mol

Volume of solution=100 ml= 0.1 L

Therefore, Molarity=\frac{no. \: of \: moles}{volume}

                              \frac{10^{-3}}{0.1} \: = 0.01 M

 


Option 1)

0.01 M

This option is correct

Option 2)

0.001M

This option is incorrect

Option 3)

0.1M

This option is incorrect

Option 4)

0.02M

This option is incorrect

Posted by

Plabita

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