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  • Answer please! A mass of 1g carrying charge q falls through a potential difference V. The kinetic energy acquired by it is E. When a mass of 2g carrying the charge q falls through a potential difference V. What will be the kinetic energy acquired by

A mass of 1g carrying charge q falls through a potential difference V. The kinetic energy acquired by it is E. When a mass of 2g carrying the charge q falls through a potential difference V. What will be the kinetic energy acquired by it

  • Option 1)

    0.25 E

  • Option 2)

    0.50 E

  • Option 3)

    0.75 E

  • Option 4)

    E

 

Answers (1)

As we have learnt,

 

when Charged Particle at rest in uniform field -

Kinetiv Energy -

K=\frac{1}{2}mv^{2}=\frac{1}{2}m\left ( \frac{QEt}{m} \right )^{2}=\frac{Q^{2}E^{2}t^{2}}{2m}

K=\frac{1}{2}m\times \frac{2Q\Delta v}{m}=Q\cdot \Delta v

-

 

In electric field kinetic energy gain by the charged particle K = qV. Which depends charge and potential difference applied but not on the mass of the charged particle. 

 


Option 1)

0.25 E

Option 2)

0.50 E

Option 3)

0.75 E

Option 4)

E

Posted by

Vakul

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