In the following sequence of reactions

CH_{3}-Br\overset{KCN}{\rightarrow}A\overset{H_{3}O^{+}}{\rightarrow}B\xrightarrow[ether]{LiAlH_{4}}C , the end product (C) is

  • Option 1)

    Acetone

  • Option 2)

    Methane

  • Option 3)

    Acetaldehyde

  • Option 4)

    Ethyl alcohol

 

Answers (1)

As we learnt in 

Alcohol formation by reduction of carboxylic acids -

Yields primary alcohol.

- wherein

RCOOH+LiAlH_{4}\rightarrow RCH_{2}OH

 

 

Preparation of alcohol -

By treatment with  ag.KOH  or moist  Ag2O

- wherein

RX+KOH(ag)\rightarrow ROH+KX


RX+Ag_{2}O(moist)\rightarrow ROH+AgX

 

 CH_{3}Br \xrightarrow{} {KCN}CH_{3}CN \xrightarrow{}{H_{3}O^{+}}CH_{3}COOH \xrightarrow {LiAlH_{4}} \underset{Ethyl\ Alcohol}{CH_{3}CH_{2}OH}

 


Option 1)

Acetone

This solution is incorrect 

Option 2)

Methane

This solution is incorrect 

Option 3)

Acetaldehyde

This solution is incorrect 

Option 4)

Ethyl alcohol

This solution is correct 

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