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Answer please! - Co-ordination Compounds - JEE Main

In K_{4}[Fe(CN)_{6}],  the E.A.N. of Fe  is

  • Option 1)

    33

  • Option 2)

    35

  • Option 3)

    36

  • Option 4)

    26

 
Answers (1)
69 Views
V Vakul

As we learned

Effective Atomic Number (EAN) -

EAN=\left ( Z-x \right )+2\times C.N.

- wherein

Z= Atomic  Number of Center Atom

x= Oxidation Number

C.N. =Coordination Number

 

 EAN =Atomic number – Oxidation state + 2 × number of Ligands =  26 – 2 + 2 (6) = 36.

 


Option 1)

33

Option 2)

35

Option 3)

36

Option 4)

26

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