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# Answer please! Five capacitors are connected as shown in the figure. The equivalent capacitance between the point A and B is

Five capacitors are connected as shown in the figure. The equivalent capacitance between the point A and B is

• Option 1)

$1 \mu f$

• Option 2)

$2 \mu f$

• Option 3)

$3\mu f$

• Option 4)

$4 \mu f$

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As we have learned

Series Grouping -

$\dpi{100} \frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots$

- wherein

Hence equivalent capacitance between A and B is $2\mu f$

Option 1)

$1 \mu f$

Option 2)

$2 \mu f$

Option 3)

$3\mu f$

Option 4)

$4 \mu f$

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