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The electrons identified by quantum numbers n and l :

(1) n = 4, l = 1 (2) n = 4, l = 0 (3) n = 3, l = 2 (4) n = 3 , l = 1

Can be placed in order of increasing energy as :

Option 1)
$(4)< (2)< (3)< (1)$

Option 2)
$(2)< (4)< (1)< (3)$

Option 3)
$(1)< (3)< (2)< (4)$

Option 4)
$(3)< (4)< (2)< (1)$

Answers (3)

best_answer

As discussed in the concept

Principal Quantum Number (n) -

It is a positive integer with value of n = 1,2,3.......

-

and

Azimuthal Quantum Number(l) -

For a given value of n, l can have n values ranging from 0 to n – 1, that is, for a given value of n, the possible value of l are : l = 0, 1, 2, ....( n –1)

-

$(1)\; n=4,l=1\Rightarrow 4p$

$(2)\; n=4,l=0\Rightarrow 4s$

$(3)\; n=3,l=2\Rightarrow 3d$

$(4)\; n=3,l=1\Rightarrow 3p$

Increasing order of energy is

$3p< 4s< 3d< 4p$

$(4)< (2)< (3)< (1)$

Alternatively,

$For\; \; \; \; (1)\; n+l=5;n=4$

$\; \; \; \; \; \; (2)\; n+l=4;n=4$

$\; \; \; \; \; \; (3)\; n+l=5;n=3$

$\; \; \; \; \; \; (4)\; n+l=4;n=3$

$Lower\; n+l\; means\; less\; energy \; and \; if\; for\; two\; subshells\; n+l\;$

$is\; same\; than\; lower\; n,lower \; will \; be\; the\; energy.$

Thus correct order is (4) < (2) < (3) < (1)

Option 1)

$(4)< (2)< (3)< (1)$

Correct option

Option 2)

$(2)< (4)< (1)< (3)$

Incorrect option

Option 3)

$(1)< (3)< (2)< (4)$

Incorrect option

Option 4)

$(3)< (4)< (2)< (1)$

Incorrect option

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