The ratio of mass percent of C and H of an organic compound (CXHYOZ) is 6 : 1. If one molecule of the above compound
(CXHYOZ) contains half as much oxygen as required to burn one molecule of compound CXHY completely to CO2 and
H2O. The empirical formula of compound CXHYOZ is :
C2H4O3
C3H6O3
C2H4O
C3H4O2
As we learned
Empirical formula -
An Empirical formula represents the simplest whole number ratio of various atoms present in a compound.
- wherein
for glucose, empirical formula is CH2O
Mass ratio of C & H is 6 :
So mole ratio of C & H is 1 : 2
X : Y = 1 : 2
To burn one molecule of
molecule of is required i.e. 3 atoms of O are required so
So empirical formula is
Option 1)
C2H4O3
Option 2)
C3H6O3
Option 3)
C2H4O
Option 4)
C3H4O2
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