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  • Arrangement of two block system is as shown in the figure . mass of block A is m _A = 5 Kg and mass of B is m _B = 10 Kg

Arrangement of two block system is as shown in the figure . mass of block A is m _A = 5 Kg 

and mass of B is m _B = 10 Kg 

A constant force F = 100 N applied on upper block A . Friction between A and B is \mu . and b/w B and ground surface is smooth , then find work done by frictional force on block B in t = 2 sec  if system starts from rest 

Answers (1)

friction force on block A, f_{k} = 0.5\times 5\times 10 = 25N

An equal and opposite force will be applied on block B

m_{b}a_{b}=f_{k}

10a_{b}=25

\Rightarrow a_{b}=2.5 m/s^{2}

s = \frac{1}{2}a_{b}t^{2}

s = \frac{1}{2}2.5\times 2^{2} = 5\: m

Work done = 25\times 5 = 125\: J

Posted by

Abhishek Sahu

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