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t_{1/4} can be taken as the time taken for the conc. of a reactant to drop to 3/4 of its value. If the rate constant for a first order reaction is k, the t_{1/4} can be written as[\ln 2=0.695,\ln 3=1.1]

Option: 1

0.69/k


Option: 2

0.75/k


Option: 3

0.10/k


Option: 4

0.29/k


Answers (1)

best_answer

The formula for the First Order Reaction -

 A_{t}= A_{0}e^{-kt}

t1/4 can be taken as the time taken for the conc. of a reactant to drop to 3/4 of its value. If the rate constant for a first-order reaction is k.

\\\ln \frac{\frac{3}{4}A_{0}}{A_{0}}= -kt_{1/4}\\\\ \ln \frac{3}{4}=-kt_{1/4}

\therefore t_{1/4}= \frac{0.29}{k}

Posted by

Sanket Gandhi

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