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  • Can someone explain An ideal capacitor of capacitance 0.2 μF is charged to a potential difference of 10 V. The charging battery is thendisconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5 mH. The current at a t

An ideal capacitor of capacitance 0.2 μF is charged to a potential difference of 10 V. The charging battery is then
disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5 mH. The current at a time
when the potential difference across the capacitor is 5 V, is :

  • Option 1)

    0.34 A

  • Option 2)

    0.25 A

  • Option 3)

    0.17 A

  • Option 4)

    0.15 A

 

Answers (1)

best_answer

As we learned

@3935

 

From energy conservation

\frac{1}{2}\times 0.2\times 10^{6}\times 10^{2}+0 = \frac{1}{2}\times 0.2\times 10^{-6}\times 5^{2}+\frac{1}{2}\times 0.5\times 10^{-3} 1^{2}

I=\frac{\sqrt{3}}{10}A = 0.17A

 


Option 1)

0.34 A

Option 2)

0.25 A

Option 3)

0.17 A

Option 4)

0.15 A

Posted by

Plabita

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