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  • Can someone explain - Chemical Bonding and molecular structure - NEET

The outer orbitals of C in ethene molecule can be considered to be hybridized to give three equivalent sp^{2} orbitals. The total number of sigma \left ( \sigma \right ) and pi \left ( \pi ) bonds in ethene molecule is

  • Option 1)

    1 sigma \left ( \sigma \right ) and 2 pi \left (\pi ) bonds

  • Option 2)

    3 sigma \left ( \sigma \right ) and 2 pi \left (\pi ) bonds

  • Option 3)

    4 sigma \left ( \sigma \right ) and 1 pi \left (\pi ) bonds

  • Option 4)

    5 sigma \left ( \sigma \right ) and 1 pi \left (\pi ) bonds

 

Answers (1)

best_answer

As we learnt in

Sigma bond -

When covalent bond is formed by overlapping of atomic orbitals along the same axis it is called Sigma bond. Such type of bond is symmetrical about the line joining the two nuclei.

- wherein

 

 And, 

 

Pi bond -

This type of bond is formed by sidewise or lateral over lapping of two half filled atomic orbitals.

- wherein

 

  

In CH_{2}=CH_{2}, the hybridized sp^{2} carbon will form 2 \sigma bonds with H & 1 \sigma bond with another C .

 

The p orbital will form a \pi bond with another p orbital of other carbon. 

The p orbital will form \alpha \pi bond with another pure partial of other carbon.

\therefore We have 5 \sigma bonds and 1 \pi bond.

 

 

 


Option 1)

1 sigma \left ( \sigma \right ) and 2 pi \left (\pi ) bonds

This option is incorrect.

Option 2)

3 sigma \left ( \sigma \right ) and 2 pi \left (\pi ) bonds

This option is incorrect.

Option 3)

4 sigma \left ( \sigma \right ) and 1 pi \left (\pi ) bonds

This option is incorrect.

Option 4)

5 sigma \left ( \sigma \right ) and 1 pi \left (\pi ) bonds

This option is correct.

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