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The input resistance of a silicon transistor is 100 \Omega. Base current is changed by \text{40}\mu \text{A} which results in a change in collector current by 2 mA. This transistor is used as a common emitter amplifier with a load resistance of 4\text{k}\Omega . The voltage gain of the amplifier is:

  • Option 1)

    3000

  • Option 2)

    4000

  • Option 3)

    1000

  • Option 4)

    2000

 

Answers (1)

best_answer

\\R_{i}= 100 \Omega \\ \Delta I_{B}=40 \mu A \\ \Delta I_{C}=2 m A \\ R_{L}=4K \Omega

Voltage gain \frac{V_{0}}{V_{i}}= \beta .\left ( \frac{R_{L}}{R_{i}} \right )

\beta =\frac{\Delta I_{C}}{\Delta I_{B}}=\frac{2 \times 10^{-3}}{4 \times 10^{-5}}=0

\therefore voltage \ gain = 50 \times \frac{4\times 10^{3}}{ 10^{2}}= 2000

 


Option 1)

3000

Incorrect option

Option 2)

4000

Incorrect option

Option 3)

1000

Incorrect option

Option 4)

2000

correct option

Posted by

divya.saini

View full answer

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