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Engineering
5 months, 3 weeks ago

# Can someone explain If an equilateral triangle, having vertexat the (2,-1), has a side along the line, x+y=2, then the area (in sq. units) of this triangle is :

If an equilateral triangle, having vertex at the (2,-1), has a side along the line, x+y=2, then the area (in sq. units) of this triangle is :

• Option 1) • Option 2)

6

• Option 3) • Option 4) Answers (2)
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A arun shelke
Answered 5 months ago

ACCORDING TO QUESTION ,WE JUST HAVE TO FIND THE PERPENDICULAR DISTANCE OF POINT (2,-1) FORM THE LINE

x + y = 2,THIS PERPENDICULAR DISTANCE IS EQUAL TO THE HEIGHT OF THE TRIANGLE FORMED,AND THEN WE CAN CALCULATE THE SIDE OF TRIANGLE,AND THEN BY APPLING FORMULA OF AREA OF TRIANGLE  {(1/2)*b*h}

SO,

DISTANCE OF POINT FRON THE LINE (h) =

AND ALSO WE KNOW THAT HEIGHT OF THE TRIANGLE =

NOW, h =  AND ALSO h =

FROM HERE WE GET THE VALUE OF a(BASE OF TRIANGLE(b)) =

NOW BY FORMULA {(1/2)*b*h} = (1/2) *   *   =  sq.units.

BUT UNFORTUNATELY NO OPTION IS MATCHING OUR ANSWER.SO, THE ANSWER IS 1/2

S solutionqc
Answered 5 months, 3 weeks ago

Option 1) Option 2)

6

Option 3) Option 4) ## Similar Questions

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