If an equilateral triangle, having vertex at the (2,-1), has a side along the line, x+y=2, then the area (in sq. units) of this triangle is :
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ACCORDING TO QUESTION ,WE JUST HAVE TO FIND THE PERPENDICULAR DISTANCE OF POINT (2,-1) FORM THE LINE
x + y = 2,THIS PERPENDICULAR DISTANCE IS EQUAL TO THE HEIGHT OF THE TRIANGLE FORMED,AND THEN WE CAN CALCULATE THE SIDE OF TRIANGLE,AND THEN BY APPLING FORMULA OF AREA OF TRIANGLE {(1/2)*b*h}
SO,
DISTANCE OF POINT FRON THE LINE (h) =
AND ALSO WE KNOW THAT HEIGHT OF THE TRIANGLE =
NOW, h = AND ALSO h =
FROM HERE WE GET THE VALUE OF a(BASE OF TRIANGLE(b)) =
NOW BY FORMULA {(1/2)*b*h} = (1/2) * * = sq.units.
BUT UNFORTUNATELY NO OPTION IS MATCHING OUR ANSWER.SO, THE ANSWER IS 1/2