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One mole of an ideal monoatomic gas is
compressed isothermally in a rigid vessel
to double its pressure at room temperature,
27^{\circ}C. The work done on the gas will be :

  • Option 1)

    300 R

  • Option 2)

    300 R ln 6

  • Option 3)

    300 R ln 2

  • Option 4)

    300 R ln 7

 

Answers (2)

best_answer

As we learned

 

work done by a gas -

\omega = \int PdV
 

- wherein

P is pressure

dV is small change in volume.

 

 w= n R T l_{n}\left ( \frac{v_{f}}{v_{i}} \right ) = n R T l_{n}\left ( \frac{p_{i}}{p_{f}} \right )

=1\times R\times 300 l_{n}\left ( \frac{1}{2} \right ) = -300 R l_{n}^{2}

work now on gas = 300 R l_{n}^{2}


Option 1)

300 R

Option 2)

300 R ln 6

Option 3)

300 R ln 2

Option 4)

300 R ln 7

Posted by

Plabita

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