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  • Can someone help me with this, - Electrostatics - JEE Main-3

The electric field near a conducting surface having a uniform surface charge density \sigma  is given by

  • Option 1)

            

    \frac{\sigma }{\varepsilon _{0}}\; \; \;   and is parallel to the surface

  • Option 2)

    \frac{2\sigma }{\varepsilon _{0}}\; \; \;  and is parallel to the surface

  • Option 3)

    \frac{\sigma }{\varepsilon _{0}}\; \; \; and is normal to the surface

  • Option 4)

    \frac{2\sigma }{\varepsilon _{0}}\; \; \; and is normal to the surface

 

Answers (1)

best_answer

As we learned

Surface charge distribution -

\left ( \sigma \right )- charge per unit Area 

\dpi{100} \sigma=\frac{Q}{A}=\frac{C}{m^{2}}=Cm^{-2}

 

- wherein

(Plane sheet, sphere, cylinder etc)

 

 Electric field near the conductor surface is given by  \frac{\sigma }{\varepsilon _{0}} and it is perpendicular to surface.

 


Option 1)

        

\frac{\sigma }{\varepsilon _{0}}\; \; \;   and is parallel to the surface

Option 2)

\frac{2\sigma }{\varepsilon _{0}}\; \; \;  and is parallel to the surface

Option 3)

\frac{\sigma }{\varepsilon _{0}}\; \; \; and is normal to the surface

Option 4)

\frac{2\sigma }{\varepsilon _{0}}\; \; \; and is normal to the surface

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