If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5%. The initial momentum of electrons will be:

  • Option 1)

    400 P

  • Option 2)

    \frac{\text{P}} 100

  • Option 3)

    100 P

  • Option 4)

    200 P

 

Answers (1)

p.\lambda =h\rightarrow 1\\ \therefore p.\Delta \lambda +\lambda .\Delta p=0\\ or\:p=\frac{-\lambda }{\Delta \lambda }.\Delta p

given \frac{\Delta \lambda }{\lambda }=0.005, \Delta p=p\\

initial momentum is p=\frac{-\Delta p}{0.005}=200p

-ve sign show change will be opposite to change in wavelength


Option 1)

400 P

This option is incorrect 

Option 2)

\frac{\text{P}} 100

This option is incorrect 

Option 3)

100 P

This option is incorrect 

Option 4)

200 P

This option is correct 

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