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In an experiment it showed that 10 ml of 0.05M solution of chloride required 10 mL of 0.1 M solution of AgNO₃ , which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):

Option 1)
X₂Cl

Option 2)
X₂Cl₂

Option 3)
XCl₂

Option 4)
XCl₄

Answers (1)

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As learnt

Stoichiometry -

Stoichiometry deals with measurements of reactants and products in a chemical reaction.

- wherein

aA (g) + bB (g) → cC (g) + dD (g)

Here, ‘a’ moles of A(g) reacts with ‘b’ moles of B(g) to give ‘c’ mole of C(g) and ‘d’ moles of D(g)

No. of moles of AgNO₃=10^-3 mol

No. of moles the chloride= 0.5 x 10^-3 mol

Suppose the formula for the chloride is XCl_n then moles of chloride ion=n x 0.5 x 10^-3

Reaction goes as follows:

$Ag^{+} \: +\: \: Cl^{-} \: \: \rightarrow AgCl$

Then, going by stoichiometry we get

n x 0.5 x 10^-3= 10^-3

n=2

Therefore, formula is XCl₂

Option 1)

X₂Cl

This option is incorrect

Option 2)

X₂Cl₂

This option is incorrect

Option 3)

XCl₂

This option is correct

Option 4)

XCl₄

This option is incorrect

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Aadil

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