# In an experiment it showed that 10 ml of 0.05M solution of chloride required 10 mL of 0.1 M solution of AgNO3 , which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): Option 1) X2Cl Option 2) X2Cl2 Option 3) XCl2 Option 4) XCl4

As learnt

Stoichiometry -

Stoichiometry deals with measurements of reactants and products in a chemical reaction.

- wherein

aA (g) + bB (g) → cC (g) + dD (g)

Here, ‘a’ moles of A(g) reacts with ‘b’ moles of B(g) to give ‘c’ mole of C(g) and ‘d’ moles of D(g)

No. of moles of AgNO3=10-3 mol

No. of moles the chloride= 0.5 x 10-3 mol

Suppose the formula for the chloride is XCln then moles of chloride ion=n x 0.5 x 10-3

Reaction goes as follows:

$Ag^{+} \: +\: \: Cl^{-} \: \: \rightarrow AgCl$

Then, going by stoichiometry we get

n x 0.5 x 10-3= 10-3

$\Rightarrow$ n=2

Therefore, formula is XCl2

Option 1)

X2Cl

This option is incorrect

Option 2)

X2Cl2

This option is incorrect

Option 3)

XCl2

This option is correct

Option 4)

XCl4

This option is incorrect

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