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  • Can someone help me with this, - Limit , continuity and differentiability - JEE Main-9

Which of the following function are diffrentiable for all x\epsilon R ?

  • Option 1)

    f(x)= x^{4}+x^{2}-1

  • Option 2)

    f(x)=2^{x}

  • Option 3)

    f(x)=1

  • Option 4)

    all of these

 

Answers (1)

best_answer

As we have learned

Properties of differentiable functions -

Every constant function is differentiable at each x\epsilon R

-

 

 (A) is polynomial , (B) is exponential and (C) is constant and we know all three are diffrentiable for all x\epsilon R 

 

 

 

 

 


Option 1)

f(x)= x^{4}+x^{2}-1

Option 2)

f(x)=2^{x}

Option 3)

f(x)=1

Option 4)

all of these

Posted by

Himanshu

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