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The edge length of a face centred cubic cell of an ionic substance is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is

  • Option 1)

    144 pm

  • Option 2)

    288 pm

  • Option 3)

    398 pm

  • Option 4)

    618 pm

 

Answers (1)

As we learnt in

Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -

-

 

 2r_{cation}+2r_{anion}=a\sqrt{2}

r_{cation}+r_{anion}=\frac{508}{1.414}

110+r_{anion}=\frac{508}{1.414}

r_{anion}=249\ PM

 

 


Option 1)

144 pm

This is an incorrect option.

Option 2)

288 pm

This is an incorrect option.

Option 3)

398 pm

This is an incorrect option.

Option 4)

618 pm

This is an incorrect option.

Posted by

Vakul

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