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  • Can someone help me with this, The orbital angular momentum of a p-electron is given as:

The orbital angular momentum of a p-electron is given as:

  • Option 1)

    \frac{h}{\sqrt 2 \pi}

  • Option 2)

    \sqrt 3 \frac{h}{ 2 \pi}

  • Option 3)

    \sqrt {\frac{3}{2}}\frac{h}{\pi}

  • Option 4)

    \sqrt 6. \frac{h}{2 \pi}

 

Answers (1)

best_answer

As learnt in

Bohr's model -

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. mvr=\frac{nh}{2\pi }

    n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfer orbit  E_{1}-E{_{2}}=h\nu

-

 

 The orbital angular momentum is given by \sqrt{l(l+1)}\frac{h}{2\pi } where l is the azimuthal quantum number for p orbital, l=1

\therefore orbital angular momentum = \sqrt{(1)(1+1)} \frac{h}{2\pi }

                                  = \sqrt{2} \frac{h}{2\pi } = \frac{h}{\sqrt{2}\pi }


Option 1)

\frac{h}{\sqrt 2 \pi}

This solution is correct

Option 2)

\sqrt 3 \frac{h}{ 2 \pi}

This solution is incorrect

Option 3)

\sqrt {\frac{3}{2}}\frac{h}{\pi}

This solution is incorrect

Option 4)

\sqrt 6. \frac{h}{2 \pi}

This solution is incorrect

Posted by

Aadil

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