Q

# Can someone help me with this, The orbital angular momentum of a p-electron is given as:

The orbital angular momentum of a p-electron is given as:

• Option 1)

$\frac{h}{\sqrt 2 \pi}$

• Option 2)

$\sqrt 3 \frac{h}{ 2 \pi}$

• Option 3)

$\sqrt {\frac{3}{2}}\frac{h}{\pi}$

• Option 4)

$\sqrt 6. \frac{h}{2 \pi}$

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As learnt in

Bohr's model -

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. $mvr=\frac{nh}{2\pi }$

n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfer orbit  $E_{1}-E{_{2}}=h\nu$

-

The orbital angular momentum is given by $\sqrt{l(l+1)}\frac{h}{2\pi }$ where l is the azimuthal quantum number for p orbital, $l=1$

$\therefore$ orbital angular momentum = $\sqrt{(1)(1+1)} \frac{h}{2\pi }$

$= \sqrt{2} \frac{h}{2\pi } = \frac{h}{\sqrt{2}\pi }$

Option 1)

$\frac{h}{\sqrt 2 \pi}$

This solution is correct

Option 2)

$\sqrt 3 \frac{h}{ 2 \pi}$

This solution is incorrect

Option 3)

$\sqrt {\frac{3}{2}}\frac{h}{\pi}$

This solution is incorrect

Option 4)

$\sqrt 6. \frac{h}{2 \pi}$

This solution is incorrect

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