What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20°C to 35°C ?
(R = 8.314 Jmol-1K-1)
15.1 kJ mol-1
342 kJ mol-1
269 kJ mol-1
34.7 kJ mol-1
As learnt in @9518
Since
K2 = 2K1 , T1 = 273 + 20 K = 293 K
T2 = 273 + 35 K = 308 K
R = 8.314 J mol-1 K-1
Option 1)
15.1 kJ mol-1
This answer is incorrect
Option 2)
342 kJ mol-1
This answer is incorrect
Option 3)
269 kJ mol-1
This answer is incorrect
Option 4)
34.7 kJ mol-1
This answer is correct