Q

# can you explain the sol?

5.325 g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758 g of Carbon, 0.316 g of Hydrogen and 1.251 g of Oxygen. What is the empirical formula of the compound?

A.

C4H4O

B.

C2H4O

C.

C2H2O

D.

C4H3O

3 Views

Option(A) is correct.
mass of C=3.758g
mass of H=0.316g
mass of O=1.251g
moles of C=3.758/12=0.3132
moles of H=0.316/1=0.316
moles of O=1.251/16=0.0782
mole %:
'C'=44.274%=44%
'H'=44.67%=44%
'O'=11.054%=11%
empirical formula of compound=$C_4H_4O$

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