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At room temperature a diatomic gas is found  to  have  an  r.m.s.  speed  of 1930 ms-1. The gas is :

 

  • Option 1)

    H_{2}

  • Option 2)

    Cl_{2}

  • Option 3)

    O_{2}

  • Option 4)

    F_{2}

 

Answers (1)

best_answer

As we have learned

Root mean square velocity -

V_{rms}= \sqrt{\frac{3RT}{M}}

= \sqrt{\frac{3P}{\rho }}
 

- wherein

R = Universal gas constant

M = molar mass

P = pressure due to gas

\rho = density

 

 At room temprature T = 300 K 

For diatomic gas 

V_{rms} = \sqrt{\frac{3RT}{M }}= \Rightarrow M = \frac{3RT}{V^2}

M= \frac{3 \times 8.3\times 300}{(1930)^2} = 2 g /mole

The diatomic gas is H_2

 

 

 

 

 


Option 1)

H_{2}

Option 2)

Cl_{2}

Option 3)

O_{2}

Option 4)

F_{2}

Posted by

Avinash

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