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The resistances in the two arms of the meter bridge are 5 \Omega and R \Omega, respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6 l1. the resistance 'R' is:

 

  • Option 1)

    10 \Omega

  • Option 2)

    15 \Omega

  • Option 3)

    20 \Omega

  • Option 4)

    25 \Omega

 

Answers (1)

best_answer

As discussed in @8177

\frac{5}{R} = \frac{l_{1}}{100- l_{1}}\: and\: \frac{5}{\frac{R}{2}} = \frac{1.6\:l_{1}}{100-1.6\:l_{1}}

\therefore R = 15\:\omega


Option 1)

10 \Omega

This answer is incorrect

Option 2)

15 \Omega

This answer is correct

Option 3)

20 \Omega

This answer is incorrect

Option 4)

25 \Omega

This answer is incorrect

Posted by

prateek

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