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Confused! kindly explain, In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :

 In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :

  • Option 1)

    CE

  • Option 2)

    CE\frac{r_{1}}{\left ( r_{2}+r \right )}

  • Option 3)

    CE\frac{r_{2}}{\left ( r+r_{2} \right )}

  • Option 4)

    CE\frac{r_{1}}{\left ( r_{1} +r\right )}

 
Answers (2)
194 Views
N neha

As we discussed in concept

Charging Of Capacitors

where in

Q=Q_{0}\left ( 1-e^{\frac{-t}{Rc}} \right )

at steady state there is no current through r1

 

Q=CE\frac{r_{2}}{\left ( r+r_{2} \right )}

 

 


Option 1)

CE

Option 2)

CE\frac{r_{1}}{\left ( r_{2}+r \right )}

Option 3)

CE\frac{r_{2}}{\left ( r+r_{2} \right )}

Option 4)

CE\frac{r_{1}}{\left ( r_{1} +r\right )}

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