Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, Two copper balls, each weighing 10g are kept in air 10 cm apart. If one electron from every 106 atoms is transferred from one ball to the other, the coulomb force between them is (atomic weight of copper is 63.5)

Two copper balls, each weighing 10g are kept in air 10 cm apart. If one electron from every 106 atoms is transferred from one ball to the other, the coulomb force between them is (atomic weight of copper is 63.5)

  • Option 1)

    2.0\times 10^{10}N

  • Option 2)

    2.0\times 10^{4}N

  • Option 3)

    2.0\times 10^{8}N

  • Option 4)

    2.0\times 10^{6}N

 

Answers (1)

As we learned

Properties of Charge -

Transferable 

- wherein

It can be transferred from one body to another.

 

 Number of atoms in given mass =  \frac{10}{63.5}\times 6.02\times 10^{23}=9.48\times 10^{22}

Transfer of electron between balls = \frac{9.48\times 10^{22}}{10^{6}}=9.48\times10^{16}

Hence magnitude of charge gained by each ball.

Q=9.48\times 10^{16}\times1.6\times10^{-19}=0.015\: C

Force of attraction between the balls  F=9\times 10^{9}\times\frac{(0.015)^{2}}{(0.1)^{2}}=2\times10^{8}N


Option 1)

2.0\times 10^{10}N

Option 2)

2.0\times 10^{4}N

Option 3)

2.0\times 10^{8}N

Option 4)

2.0\times 10^{6}N

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in
anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation

Latest Question