Consider an YDSE that has different slit widths. As a result, amplitude of waves from two silts are A and 2A respectively. If I_{0} be the maximum intensity of the interference pattern, then intensity of the pattern at a point where phase difference between waves is \phi  is:

Answers (1)

As amplitudes are A and 2A, so intensities would be in the ratio 1:4, let us say I and 4I

\begin{aligned} &I_{\max }=I_{0}=I+4 I+2 \sqrt{4 i^{2}}=9 I \Rightarrow I=I_{0} 9\\ &\text { Intensity at any point, } I^{\prime}=I+4 I+2 \sqrt{4 I^{2}} \cos \phi\\ &I^{\prime}=5 I+4 I \cos \phi=\frac{I_{0}}{9}(5+4 \cos \phi) \end{aligned}

 

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