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Consider the following conversion:

The order in which the following reagents have to be used to carry out the given conversion is :

\mathrm{(i)\ CH_3Cl/AlCl_3}

\mathrm{(ii)\ KMnO_4,H^+}

\mathrm{(iii)\ \Delta}

\mathrm{(iv)\ conc.\ HNO_3,conc.\ H_2SO_4}

Option: 1

\mathrm{(i),(ii), (iii),(iv)}


Option: 2

\mathrm{(iv),(i), (ii),(iii)}


Option: 3

\mathrm{(i),(ii), (iv),(iii)}


Option: 4

\mathrm{(i),(iv), (ii),(iii)}


Answers (1)

The reaction will be -


Therefore, the correct option is (4)

Posted by

Sumit Saini

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