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  • Consider the Hunsdiecker reaction given below <img alt="\mathrm{RCOOAg+Br_2 \xrightarrow[Reflux]{CCl_4} R-Br+CO_2+AgBr}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BR

Consider the Hunsdiecker reaction given below

\mathrm{RCOOAg+Br_2 \xrightarrow[Reflux]{CCl_4} R-Br+CO_2+AgBr}

What should be the order of reactivity of the above reaction if R is 1^{\circ},2^{\circ},3^{\circ} Carbon.

Option: 1

 1^{\circ}>2^{\circ}>3^{\circ}


Option: 2

3^{\circ}>2^{\circ}>1^{\circ}


Option: 3

2^{\circ}>3^{\circ}>1^{\circ}


Option: 4

2^{\circ}>1^{\circ}>3^{\circ}


Answers (1)

best_answer

As we have learnt,

The reaction mechanism involves formation of free radicals and 1o carbon free radicals will react faster due to lesser steric hinderance followed by 2o and then 3o.

Therefore, option (1) is correct.

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