Despite having the aldehyde group, Glucose does not give Schiff's test. This is because
Glucose have five -OH group.
Glucose does not have any carbonyl group.
Carbonyl group is not free in glucose.
None
As we have learnt,
Aldehyde group in D- Glucose is not completely free. It is involved in hemi acetal formation with the hydroxyl group at C-5 to form a cyclic structure as represented in the Haworth projection given below:
Hence, the correct answer is Option (3)
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