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Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube. K-shell electrons of tungsten have -72.5 keV energy. X-rays emitted by the tube contain only,

Option: 1

A continuous X-ray spectrum with a minimum wavelength of ≈0.155\AA


Option: 2

A continuous X-ray spectrum (Bremsstrahlung) with all wavelengths


Option: 3

The characteristic X-ray spectrum of tungsten


Option: 4

A continuous X-ray spectrum (bremsstrahlung) with a minimum wavelength of \approx 0.0155 \mathrm{~nm} and the characteristic X-ray spectrum of tungsten


Answers (1)

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The minimum wavelength of continuous spectrum \lambda=\mathrm{hc} / \mathrm{E}

\lambda=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{80 \times 10^{3} \times 1.6 \times 10^{-19}}

Apart from continuous X-rays, as the energy of the incident electrons is greater than the magnitude of the energy of the K-shell electrons, the target atoms will have vacancies in the K shell (K-shell electrons will be knocked out). This will cause the emission of the entire characteristic spectrum of tungsten.

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jitender.kumar

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