Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Energy of an electron is given by   <img alt="E=-2.178\times 10^{-18}J\left ( \frac{Z^{2}}{n^{2}} \right )" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cinline%20%5Cdpi%7B100%7D%20E%

Energy of an electron is given by   E=-2.178\times 10^{-18}J\left ( \frac{Z^{2}}{n^{2}} \right ),Wavelength of light required to excite an electron in a hydrogen atom from level n = 1 to n = 2 will be:

(h=6.62\times10-34Js and c = 3.0 \times108 ms-1)

Option: 1

8.500\times10-7 m


Option: 2

1.214\times10-7 m


Option: 3

2.816\times10-7 m


Option: 4

6.500\times10-7 m


Answers (1)

best_answer

The total energy of electron in nth orbit -

E_{n}= -13.6\: \frac{z^{2}}{n^{2}}eV

Where z is the atomic number

 \Delta E = 2.175 \times 10^{-18} z^{2} \left [ \frac{1}{{n_{1}}^{2}} - \frac{1}{n_{2}^{2}} \right ]

 

\frac{hc}{\lambda } = 2.18 \times 10^{-18} \times1^{2} \left [ \frac{1}{{1}^{2}} - \frac{1}{2^{2}} \right ]

\frac{1}{\lambda } = \frac{2.18 \times 10^{-18}}{6.62 \times 10^{-34} \times 3 \times 10^{8}} \times \frac{3}{4}

\lambda = 1.214 \times 10^{-7} m

Posted by

Gautam harsolia

View full answer

Similar Questions

Trending Articles/News

anam-khan

TS EAMCET seat allotment 2024 out for phase 1 BiPC counselling; report by October 30

Latest Question