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Equation of tangent of circle x^2+y^2+4x+4y+4=0 from point P(0,0) will be?

Option: 1

x=0


Option: 2

y=0


Option: 3

y=x 


Option: 4

A and B both


Answers (1)

best_answer

 

 

Tangent from a Point to the Circle (NEW) -

Tangent from a Point to the Circle (NEW)

  • If a point lies outside of a circle (here point is P), the two tangents can be drawn. Here, PQ and PR are two tangents.

  • If a point lies on the circle, then one tangent can be drawn. Here, ACB be a tangent

  • If a point lies inside the circle, then no tangent can be drawn.

Two real tangents can be drawn from a given point to the circle if the point lies outside the circle.

 

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x^2+y^2+4x+4y+4=0 \Rightarrow (x+2)^2+(y+2)^2=4\\ \text{circle centre at (-2,-2) and radius r=2}\\

from the above the image we can see that it has two tangents x=0 and y=0

Posted by

Divya Prakash Singh

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