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  • Find the equation to the tangent of circle  at the point (5,1)&nbsp

Find the equation to the tangent of circle x^2 + y^2 = 26 at the point (5,1) 

Option: 1

x + 5y = 26 


Option: 2

5x + y = 26 


Option: 3

x +5y = \sqrt {26 }


Option: 4

5x +y = \sqrt {26 }


Answers (1)

best_answer

Here x1 = 5, y1 = 1

So equation of tangent to given circle at (5,1) is

xx1 + yy1 = 26

Thus ,we get  5x + y = 26

Posted by

Ajit Kumar Dubey

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