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Find the radical axis of the two circles x^{2}+y^{2}+4 x+6 y+9=0 and x^{2}+y^{2}+3 x+8 y+10=0

Option: 1

x-2 y-3=0


Option: 2

x-2y-1=0


Option: 3

x-3 y+3=0


Option: 4

2x-3 y+3=0


Answers (1)

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\\\text{The equation of the radical axis is} \\ \left(x^{2}+y^{2}+4 x+6 y+9\right)-\left(x^{2}+y^{2}+3 x+8 y+10\right)=0 \\ \Rightarrow \quad x-2 y-1=0

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Shailly goel

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