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Find the value of  \frac{d}{dx}(|x^3|) at x = -2

Option: 1

-12


Option: 2

-6


Option: 3

12


Option: 4

6


Answers (1)

best_answer

As we know,

Derivative of the Polynomial Function

\mathrm{\mathbf{\frac{\mathit{d}}{\mathit{dx}}(x^n)=nx^{n-1}}}

and

\;\;\;\;\mathrm{\mathbf{\frac{\mathit{d}}{\mathit{dx}}(|x|)=\frac{|x|}{x}}

 

Now

\\|x^3|=|x| \cdot x^2\\\\ \frac{d}{dx}(|x^3|)=2x \cdot |x|+x^2 \cdot \frac{|x|}{x}=3x|x|\\\\\therefore \frac{d}{dx}(|x^3|)_{(x=-2)}=-12

Posted by

seema garhwal

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