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A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012/sec. What is the force constant of the bonds connecting one atom with the other ? (Mole wt. of silver=108 and Avagadro number=6.02×1023 gm mole−1)

  • Option 1)

    5.5 N/m
     

  • Option 2)

    6.4 N/m
     

  • Option 3)

     7.1 N/m
     

  • Option 4)

    2.2 N/m

 

Answers (3)

best_answer

T=2\pi \sqrt{\frac{m}{K}}

K=(4\pi ^{2}).\frac{m}{T^{2}}=4\pi ^{2}mf^{2}

K=4\pi ^{2}*\frac{108*10^{-3}}{6.02*10^{23}}\: *10^{24}

K=7.1\: N/m


Option 1)

5.5 N/m
 

This is incorrect

Option 2)

6.4 N/m
 

This is incorrect

Option 3)

 7.1 N/m
 

This is correct

Option 4)

2.2 N/m

This is incorrect

Posted by

prateek

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7.06 N/m

Posted by

FAISAL ANSARI

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