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For Na^{+}, Mg^{2+}, F^{-} and O^{2-}; the correct order of increasing ionic radii is :

  • Option 1)

    O^{2-}< F^{-}< Na+< Mg^{2+}

     

     

     

  • Option 2)

    Na+< Mg^{2}+< F^{-}< O^{2-}

  • Option 3)

    Mg^{2}+< Na+< F^{-}< O^{2-}

  • Option 4)

    Mg^{2}+<O^{2-}< Na^{+}< F^{-}

 

Answers (1)

As we learned

 

Size of isoelectronic species -

Smaller the value of  z/e, larger the size of that species.Smaller z means effective nuclear charge is small hence size is large.

-

 

 Isoelectronic Series :Mg^{+2}< Na^{+}< F^{-}< O^{2-}
When Negative charge increases, the radius of negatively charged ion also increased


Option 1)

O^{2-}< F^{-}< Na+< Mg^{2+}

 

 

 

Option 2)

Na+< Mg^{2}+< F^{-}< O^{2-}

Option 3)

Mg^{2}+< Na+< F^{-}< O^{2-}

Option 4)

Mg^{2}+<O^{2-}< Na^{+}< F^{-}

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